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|-- [mailto:firstname.lastname@example.org Alec Wysoker]||-- [[mailto:email@example.com|Alec Wysoker]]|
Inheriting handles in child process
In subprocess.Popen, if you pass None for any of stdin, stdout or stderr args (the default), then the subprocess is supposed to inherit the corresponding parent process handle. However, if you used py2exe to create a Windows program as opposed to a console program, and you launched the py2exe program by clicking rather than by running if from a command window, then the parent process has no handle to inherit. subprocess.Popen will throw an exception. In some instances it will throw "TypeError: an integer is required" because GetStdHandle returns None. In other cases it will throw "WindowsError: [Errno 6] The handle is invalid" as shown in the traceback below:
File "subprocess.pyc", line 533, in __init__ File "subprocess.pyc", line 607, in _get_handles File "subprocess.pyc", line 634, in _make_inheritable WindowsError: [Errno 6] The handle is invalid
This bug appears to be present up through at least Python 2.5.1 and can be found at http://sourceforge.net/tracker/index.php?func=detail&aid=1124861&group_id=5470&atid=105470
The solution is not to pass None but rather specify a handle for any of stdin, stdout and stderr that you don't want to pipe.
Note also that when you create a windows program with py2exe, sys.stderr is not a normal file object, so you can't use that, but you can use sys.stderr._file buried inside it.
if hasattr(sys.stderr, 'fileno'): childstderr = sys.stderr elif hasattr(sys.stderr, '_file') and hasattr(sys.stderr._file, 'fileno'): childstderr = sys.stderr._file else: # Give up and point child stderr at nul childStderrPath = 'nul' childstderr = file(childStderrPath, 'a') child = subprocess.Popen(...other args... stderr = childstderr)
Controlling appearance of child process created with py2exe
Suppose you want to launch a child process that is a py2exe program. If you want to communicate with the child process via pipes attached to stdin or stdout, then you must make it a console process. If you make it a windows process, then sys.stdout is replaced with a Blackhole object that throws an exception when written to. However, if you make it a console process, then, if it launched from a non-console process a console window appears - ugly. The solution is to make the child process a console process, but tell subprocess to launch it without a console window.
child = subprocess.Popen(...other args... creationflags = win32process.CREATE_NO_WINDOW)
-- Alec Wysoker